Question

(2/3)'3×(2/3)'6=(4/9)'2k-3​

Answer 1

Step-by-step explanation:

k = 15

-

4

................is the answer bro

Answer 2

Given:

$(2/3)^{3}$×$(2/3)^{6}$=$(4/9)^{2k-3}$

To Find:

The value of k

Solution:

As we know that if the base is same the powers get added

so,

$(2/3)^{3+6}$ = $(4/9)^{2k-3}$  

$(2/3)^{9}$ = $\frac{(4/9)^{2k} }{(4/9)^{-3} }$

$(2/3)^{9}$×$(4/9)^{-3}$ = $(4/9)^{2k}$

$(2/3)^{9}$×$(2/3)^{2(-3)}$ = $(4/9)^{2k}$

$(2/3)^{3}$ = $(2/3)^{2(2k)}$

comparing both the equations we get

3 = 4k ( base is same so powers are also same)

k = 3/4

Hence, the value of k = 3/4