Math, asked by ahilnaqvi786, 3 months ago

-2/3 + 3/-2
Plz explain step by step​

Answers

Answered by nandanaMK
4

 \tt \large \frac{ - 2}{ \:  \:  \: 3}  +  \frac{ \:  \:  \:  3}{ - 2}

The negative sign in the denominator will come to the numerator .

 \tt \large \frac{ - 2}{ \:  \:  \: 3}  +  \frac{ - 3}{   \:  \:  \: 2}

Here , the LCM is 3 × 2 = 6 ,

So , we will make the denominators same that is , 6 by multiplying the first term by 2 and the second term by 3.

We we multiply the denominator, we should multiply the numerator also with the same number.

 \tt \large \frac{ - 2 \times 2}{ \:  \:  \: 3 \times 2}  +  \frac{ - 3 \times 3}{   \:  \:  \: 2 \times 3}

 \tt \large \frac{ - 4}{ \:  \:  \: 6}  +  \frac{ - 9}{   \:  \:  \: 6}

 \large \tt \frac{ - 4 +  - 9}{6}

 \large \tt   \underline{\underline{\frac{ - 13}{ \:  \:  \: 6} }}

 \\  \\  \color{lime}{ \bf{Hope \:   \: this \:   \: helps  \: \:  you \: !}}

If you have any doubt regarding this Question , do post it in ur next question. :)


ᏞovingHeart: use \dfrac{?}{?} for big fractions
Answered by Mbappe007
0

Answer:

\tt \large \frac{ - 2}{ \: \: \: 3} + \frac{ \: \: \: 3}{ - 2}

3

−2

+

−2

3

● The negative sign in the denominator will come to the numerator .

\tt \large \frac{ - 2}{ \: \: \: 3} + \frac{ - 3}{ \: \: \: 2}

3

−2

+

2

−3

Here , the LCM is 3 × 2 = 6 ,

● So , we will make the denominators same that is , 6 by multiplying the first term by 2 and the second term by 3.

● We we multiply the denominator, we should multiply the numerator also with the same number.

\tt \large \frac{ - 2 \times 2}{ \: \: \: 3 \times 2} + \frac{ - 3 \times 3}{ \: \: \: 2 \times 3}

3×2

−2×2

+

2×3

−3×3

\tt \large \frac{ - 4}{ \: \: \: 6} + \frac{ - 9}{ \: \: \: 6}

6

−4

+

6

−9

\large \tt \frac{ - 4 + - 9}{6}

6

−4+−9

\large \tt \underline{\underline{\frac{ - 13}{ \: \: \: 6} }}

6

−13

\begin{gathered} \\ \\ \color{lime}{ \bf{Hope \: \: this \: \: helps \: \: you \: !}}\end{gathered}

Hopethishelpsyou!

If you have any doubt regarding this Question , do post it in ur next question. :)

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