2-3 34°, bc8
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Let coordinate of P are (h,t)A(2,3),B(3,−4)
point P will lies on the both side of AB and the
Area of triangle PAB =
2
1
(h(3−4)+2(4−k)−3(k−3))
±8.5=
2
1
[h(−1)+8−2k−3k+9]
±17=−h+8−5x+9
taking
′
+
′
sign
17+h−17+5k=0
h+5k=0
∴ locus of P is
x+5y=0
taking -ve sign
−17+h+5k−17=0
h+5k=34
∴ locus of P is
x+5y=34
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