Math, asked by payalgulecha23, 9 months ago

2÷3(3x-2)=4÷5(2x-3)-4÷3​

Answers

Answered by imransulaimani
4

Step-by-step explanation:

solve:.2÷3 (3x-2)=4÷5(2x-3)-4÷3

=(6x-4)/3=(8x-12)/5-4/3

=(6x-4)/3=3(8x-12)-20/15

=(6x-4)/3=24x-36-20/15

=(6x-4)/3=24x-56/15

=15 (6x-4)=3 (24x-56)

=90x-60=72x-168

=90x-72x=-168+60

=18x= -108

=x= -108/18

=x= -6

Answered by mddilshad11ab
10

Answer:

2  \div 3(3x - 2) = 4 \div 5(2x - 3) - 4 \div 3 \\  =  >  \frac{2}{3} (3x - 2) =  \frac{4}{5} (2x - 3) -  \frac{4}{3}  \\  =  >  \frac{6x - 4}{3}  =  \frac{8x - 12}{5}  -  \frac{4}{3}  \\  =  >  \frac{6x - 4}{3}  =  \frac{24x - 36 - 20}{15}  \\  =  > 90x - 60 = 72x - 168 \\  =  > 90x - 72x =  - 168 + 60 \\  =  > 18x =  - 108 \\  =  > x =- 6

hope it will be helpful

Similar questions