Math, asked by murarilalsharma24, 6 months ago

2/3(3x-2) =4/5(2x-3)-4/3​

Answers

Answered by nandika32
4

Step-by-step explanation:

Answer...................

Attachments:
Answered by Akash1101
2

x in (-oo:+oo)

(2/3)*(3*x-2) = (4/5)*(2*x-3)-(4/3) // - (4/5)*(2*x-3)-(4/3)

(2/3)*(3*x-2)-((4/5)*(2*x-3))+4/3 = 0

(2/3)*(3*x-2)+(-4/5)*(2*x-3)+4/3 = 0

2/3*(3*x-2)-4/5*(2*x-3)+4/3 = 0

(2/3*3*(3*x-2))/3+(-4/5*3*(2*x-3))/3+4/3 = 0

2/3*3*(3*x-2)-4/5*3*(2*x-3)+4 = 0

6/5*x+16/5+4 = 0

6/5*x+36/5 = 0

(6/5*x+36/5)/3 = 0

(6/5*x+36/5)/3 = 0 // * 3

6/5*x+36/5 = 0

6/5*x+36/5 = 0 // - 36/5

6/5*x = -36/5 // : 6/5

x = -36/5/6/5

x = -6

x = -6

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