Question

2-3-4 =0
3-0-17=0
-=?​

Answer 1

Step-by-step explanation:

The points a(0,17/3) and c(1,5) will lie on the linear equation.

For the eh given points a(0,17/3), b(2,6), c(1,5), and d(5,1) to lie on the linear equation 2(x+1)+3(y-2)=13 , the points must satisfy the given linear equation.

For point a(0,17/3)-

L.H.S of the equation = 2(0+1)+3(17/3 -2)

= 2 +11 = 13 = R.H.S

Thus the point a(0,17/3) lies on the line.

For point b(2,6)-

L.H.S of the equation = 2(2+1)+3(6-2)

= 6 +12 = 18 ≠ R.H.S

Thus the point b(2,6) doesn't lie on the line.

For point c(1,5)-

L.H.S of the equation = 2(1+1)+3(5 -2)

= 4 + 9 = 13 = R.H.S

Thus the point c(1,5) lies on the line.

For point d(5,1)-

L.H.S of the equation = 2(5+1)+3(1-2)

= 12 -3 = 9 ≠ R.H.S

Thus the point d(5,1) doesn't lie on the line.