Math, asked by janadhirenjana, 9 months ago

2+3+4=11. 3+4+5=15. 4+5+6=19. 7+8+9=? Solve it and what is the answer?

Answers

Answered by srinusavitha
12

Answer:

The answer is 33. since for every sun the digits are added and first digit is added again

7+8+9=26+7=33

Answered by GulabLachman
6

2+3+4=11. 3+4+5=15. 4+5+6=19. 7+8+9=31

Let us first try to identify the logic of the given sequence.

If we first do the addition of the three numbers, then we add the first number to the sum obtained, we get the final result.

For the first sequence, the three numbers are 2,3,4 and their sum is:

(2+3+4) = 9.

Then, we add the first no. 2 to it, and we get 9 + 2 = 11, which is the first number.

For the second sequence, the three numbers are 3,4,5 and their sum is:

(3+4+5) = 12.

Then, we add the first no. 3 to it, and we get 12 + 3 = 15, which is the second number.

For the third sequence, the three numbers are 4,5,6  and their sum is:

(4+5+6) = 15.

Then, we add the first no. 4 to it, and we get 15 + 4 = 19, which is the third number.

For the fourth sequence, the three numbers are 7,8,9 and their sum is:

(7+8+9) = 24.

Then, we add the first no. 7 to it, and we get 24 + 7 = 31, which is the required number.

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