2[3]4=14 3[4]6 =60 4[5]7=?
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Forumla:[(a*b)+(c*a)](c-a)
2(3)4=[(2*3)+(4*2)](4-3)=14
3(4)6=[(3*4)+(6*3)](6-4)=30
4(5)7=[(5*4)+(7*4)](7-5)=96
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