2/3,4/8,11/18,37/38,?
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Given : 2/3,4/8,11/18,37/38 , ?
To find : missing number
Solution:
2/3 . 4/8 , 11/18 . 37/38 ?
Lets spilit it intotwo series one for numerator and one for denominator
Numerator
2
2 * 1 + 2 = 4
4 * 2 + 3 = 11
11 * 3 + 4 = 37
37 * 4 + 5 = 153
Tₙ₊₁ = Tₙ * (n) + n + 1
Denominator
3
3 * 2 + 2 = 8
8 * 2 + 2 = 18
18 * 2 + 2 = 38
38 * 2 + 2 = 78
Tₙ₊₁ = Tₙ * 2 + 2
153 / 78 would be the next number in series
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