Math, asked by kumareshofficial1, 11 hours ago

(2+√3)⁴-8(2+√3)³+18(2+√3)²-8(2+√3)+2​

Answers

Answered by simmirawat85
0

Step-by-step explanation:

Answer · 1. i) (3)⁻² = 1/(3)² = 1/9 iv) (6)² = 36 · 2. i) (-4)⁵ / (-4)⁸ = (-4)⁵⁻⁸= (-4)⁻³ = 1/(-4)³ = 1/(-64).

Answered by vikkiain
1

1

Step-by-step explanation:

Given \: ,(2+√3)⁴-8(2+√3)³+18(2+√3)²-8(2+√3)+2 \\ =  (2 +  \sqrt{3} ) \{ (2+√3)³-8(2+√3)²+18(2+√3)-8\} + 2 \\  = (2 +  \sqrt{3} ) \{  {2}^{3}  + ( \sqrt{3} )^{3}  + 3 \times 2 \times  \sqrt{3} (2 +  \sqrt{3} )  - 8( {2}^{2}  + ( \sqrt{3} )^{2} + 2 \times 2 \times  \sqrt{3}  ) + 36 + 18 \sqrt{3}  - 8\} + 2 \\  = (2 +  \sqrt{3} ) \{ 8 + 3 \sqrt{3}  + 12 \sqrt{3} + 18 - 8(4 + 3 + 4 \sqrt{3} )  + 36 + 18 \sqrt{3}  - 8\} + 2 \\  = (2 +  \sqrt{3} ) \{ 54 + 33 \sqrt{3} - 32 - 24 - 32 \sqrt{3}  \} + 2 \\  = (2 +  \sqrt{3} ) ( \sqrt{3}  - 2)+ 2 \\  = ( \sqrt{3}  + 2)( \sqrt{3}  - 2) + 2 \\  = ( \sqrt{3} )^{2}  -  {2}^{2}  + 2 \\  = 3 - 4 + 2 \\  = 1

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