Question

2/3(4x-1)-{4x-1-3x/2}=x-7/2

Answer 1

$2 \div 3(4x - 1) - (4x - 1 - 3x \div 2) = x - 7 \div 2 \\ \frac{8x - 2}{3} (1 + \frac{3x}{2} )= x - \frac{7}{2} \\ \frac{8x - 2}{3} \times \frac{2 + 3x}{2} = \frac{2x - 7}{2} \\ (8x - 2)(2 + 3x) = 6x - 21 \\ 24 {x}^{2} + 16x - 4 - 6x - 6x + 21 = 0 \\ 24 {x}^{2} + 4x - 17 = 0$

Answer 2

Answer:

Step-by-step explanation:

2/3(4x-1)-[4x-{(1-3x)/2}]=(x-7)/2

8x/3-2/3-[(8x-1+3x)/2]=(x-7)/2

8x/3-2/3-[(11x-1)/2]=(x-7)/2

8x/3-2/3-[11x/2-1/2]=(x-7)/2

8x/3-2/3-11x/2+1/2=(x-7)/2

Now LCM of 2 and 3 is 6 so,

(16x-4-33x+3)/6=(x-7)/2

(-17x-1)/6=(x-8)/2

By cross multiplying

2(-17x-1)=6(x-7)

-34x-2=6x-42

-34x-6x=-42+2

-40x=-40

Minus and minus on both the side will cut so,

40x=40

taking 40 from LHS to RHS

x=40/40

x=1 is the answer