Question

(2/3)^5×(2/3)^6=(3/2)^3x+4​

Answer 1

Step-by-step explanation:

Given,

(x−5)

5

(2x−7)

6

x

2

(3x−4)

3

(x−2)

4

≤0

⇒

2x−7

3x−4

≤0 and x=0,2,



=7/2

⇒

3

4

≤x<5 and x=0,2,



=7/2

Hence, number of integral solution is {0,2,3,4}=4

And number of positive integral solution are 2,3,4

Thus the number of integral solutions are 3

Answer 2

Answer:

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