2^-3×5^-5×10^2×25/5^4×2^-5
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Answered by
1
Answer:
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Answered by
1
Step-by-step explanation:
Using BODMAS (BRACKETS OFF DIVIDE MULTIPLICATION ADDITION SUBTRACTIO N)
First braces need to be solved. Now here in question we can see three different types of brackets long[], curly{} and small or round().
Out of it first small need to be resolved than curly and atlast long .
So,
25-5[2+3{2-2(5-3)+5}-10]÷4
25-5[2+3{2-2(2)+5}-10]÷4
Here 2(2)=4
25-5[2+3{2–4+5}-10]÷4
here 2 and 5 are added
25-5[2+3{7-4}-10]÷4
25-5[2+3{3}-10]÷4
Here 3 and 3 are multiplied
25-5[2+9-10]÷4
Here 2 and 9 are added
25-5[11-10]÷4
25-5[1]÷4
Here 5 is multiplied with 1
25-5÷4
25–1.25
23.75 is answer
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