Question

2÷√3-√5 rationalise the denominator of the following

Answer 1

⇒2÷(√3-√5)

⇒2*( √3+√5)/(3-5)   (multiply Nmr & Dmr by √3+√5)

⇒2*(√3+√5)/-2

⇒ - (√3+√5)

Answer 2

Answer:

$\frac{2}{ \sqrt{3} - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{ \sqrt{ 3} + \sqrt{5} } \\ = \frac{2 \sqrt{3} + 2 \sqrt{5} }{( \sqrt{3} )^{2} - (\sqrt{5}) ^{2} } \\ = \frac{2 \sqrt{3} + 2 \sqrt{5} }{3 - 5} \\ = \frac{ - 2 ( - \sqrt{3} - \sqrt{5} ) }{ - 2} \\ = - \sqrt{3} - \sqrt{5}$