Question

(2/3) ^6×(2/3) ^x=(3/2) ^(-6) ×(2/3) ^4 is​

Answer 1

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Let the age of father be x years

Let the age of one of his children be y years and age of other children be z years

From given information,

x=2×(y+z)...(1)

After 20 years,

(x+20)=(y+20)+(z+20)...(2)

Substituting value of (1) in (2), we get

2×(y+z) +20=y+z+40

2y+2z−y−z=40−20

y+z=20...(3)

Substituting value of (3) in (1), we get

x=2×(20)

⇒x=40

Answer 2

Answer:

3–18+2= - 17

i.e BY USING BODMAS RULE,

B: Brackets

O: Of

D: Division

M: Multiplication

A: Addition

S: Subtraction