Question

(2√3) / (√6 + 2)
rationalise the denominator ​

Answer 1

Answer:

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Step-by-step explanation:

(2√3) /(√6 + 2)×-(√6+2)/-(√6+2)

Answer 2

Rationalisation :-

$\frac{(2 \sqrt{3}) }{( \sqrt6 + 2)} \\ = \frac{(2 \sqrt{3)} }{( \sqrt{6} + 2)} \times \frac{( \sqrt{6} - 2 )}{ (\sqrt{6} - 2)} \\ = \frac{2 \sqrt{3} ( \sqrt{6} ) - 2 \sqrt{3} (2) }{6 - 4} \\ = \frac{2 \sqrt{18} - 4 \sqrt{3} }{2}$

Hence the denominator has been rationalised.

Here at one step (√6 + 2) × (√6 - 2) became 6 - 4.

Because (a+b)(a-b) = a² - b², here a = √6 and b = 2

so √6² - 2² = 6-4

hope it helps.