2,3,7,25,121,,721,?,wht will be next no
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Hi there!
Given,
No. series is
2, 3, 7, 25, 121, 721, ?
Here, the series goes as
kth term= [k×(k-1)th term]-(k-1)
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
This is how it can be shown below:
1st term= 2
(2)nd term= [(2)×(previous term)]-(2-1)
=[(2)(2)]-1
=3
(3)rd term = [(3)×(previous term)]-(3-1)
=[(3)×(3)]-2
=7
:
:
:
://y
:
:
:
(7)th term= [(7)×(sixth term)]-6
= [7*721]-6
= 5041
•°• The required no. is 5041
hope it helps
;)
Given,
No. series is
2, 3, 7, 25, 121, 721, ?
Here, the series goes as
kth term= [k×(k-1)th term]-(k-1)
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
This is how it can be shown below:
1st term= 2
(2)nd term= [(2)×(previous term)]-(2-1)
=[(2)(2)]-1
=3
(3)rd term = [(3)×(previous term)]-(3-1)
=[(3)×(3)]-2
=7
:
:
:
://y
:
:
:
(7)th term= [(7)×(sixth term)]-6
= [7*721]-6
= 5041
•°• The required no. is 5041
hope it helps
;)
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