Question

[(2/3)^7]^5×(2/3)-^35​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

${ {(( \frac{2}{3} })^{5} ) }^{7} \times {( \frac{2}{3} })^{ - 35} \\ = {( \frac{2}{3} })^{5 \times 7} \times {( \frac{2}{3} })^{ - 35} \\ = {( \frac{2}{3} })^{35} \times {( \frac{2}{3} })^{ - 35} \\ = {( \frac{2}{3} })^{35 + ( - 35)} \\ = { (\frac{2}{3} })^{35 - 35} \\ = {( \frac{2}{3} })^{0} \\ = 1$

hope it works