Question

2+3=8 how can find how to find plz solve and send me plz how can find 8 answer​

Answer 1

QUESTION :

If 2+3=8, 3+7=27, 4+5=32, 5+8=60, and 6+7=72, how would one solve 7+8=?

ANSWER :

The law of formation of numbers on the right-side of the given equalities is as follows. Take the sum of the first two digit numbers on the left. Subtract 1 from this sum and then multiply the result so obtained by the first number on the left. What you get is the number on right-side.

Thus,

2+3 = (2+3–1) x 2 =( 5–1) x 2 = 4x2 = 8 = R.H.S.

3+7 = (3+7–1) x 3 = 9x3 = 27 = R.H.S.4+5 = (4+5-1) x 4 = 8x4 = 32 = R.H.S.

5+8 = (5+8–1) x 5 = 12 x 5 = 60 = R.H.S.6+7 = (6+7–1) x 6 = 12 x 6 = 72 = R.H.S.

Following the above logic,7+8 = (7+8–1) x 7 = 14 x 7 = 98 (Proved)