Math, asked by sidduchandan7196, 10 months ago

(2/3 a2b2c2 4/3 ab2c2)÷1/2 abc

Answers

Answered by faizanahmed423

Answer:

Step-by-step explanation:

(2/3 a2b2c2 4/3 ab2(2(2/3 a2b2c2 4/3 ab2c2)÷1/2 abc/3 a2b2c2 4/3 ab2c2)÷1/2 abcc2)÷1/2 (2/3 a2b2c2 4/(2/3 a2b2c2 4/3 ab2c2)÷1/2 abc3 ab2c2)÷1/2 abcabc

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