Question

(2,-3)&(10,p) distance is 10m and find p value user distance farmula maths​

Answer 1

Answer:

distance between the points (2,-3) and (10,p)

is √{(10-2)^2+(p+3)^2} unit

=√{8^2+p^2+6p+9} unit

=√(64+p^2+6p+9) unit

=√(p^2+6p+73)

according to question,

√(p^2+6p+73)=10

=> p^2+6p+73=10^2=100

=> p^2+6p+73-100=0

=> p^2+6p-27=0

=> p^2+9p-3p-27=0

=> p(p+9)-3(p+9)=0

=> (p+9) (p-3)=0

=> p+9=0

=> p= -9

again, p-3=0

=> p=3

so, value of p = 3 , -9