Math, asked by aaruraj09, 7 months ago

(-2,-3) are zeros of the polynomial of the form ax²+bx+c, find the factor of it.​

Answers

Answered by tennetiraj86
2

Step-by-step explanation:

given \: zeroes \: are \:  - 2 \: and \:  - 3 \\  \: let \: they \: be \:  \alpha  =  - 2 \: and \:  \beta  =  - 3 \\  \: we \: know \: that \:  \\  \: if \:  \alpha  \: and \:  \beta  \: are \: the \: zeroes \: then \: the \: polynomial \: is \:  \\  \: k( {x}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta ) \:  \\  =  > k( {x}^{2}  - ( - 2+ ( - 3))x + ( - 2)( - 3)) \\  \:  =  > k( {x}^{2}  - ( - 5)x + (6)) \\  \:  =  > k( {x}^{2}  + 5x + 6) \\  \: if \: k = 1 \: then \: the \: required \: polynomial \: is \\  \:  {x}^{2}  + 5x + 6. \\  \: the \: factoisation \: is \: (x  +  2)(x  + 3)

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