Question

2'
3
if the speed of a bus is x km/hr in first hour, (x + 2y) km/hr in second hour and (2x - y)
km/hr in the third hour. Then find the distance travelled by the bus in three hours.​

Answer 1

Answer:

4x+ y

Explanation:

a) in 1st hour-

speed= x km/h

time= 1 hour , so distance= speed/time

distance= x km

b) in 2nd hour

speed = x+2y km/h

time= 1 hour

distance = x+2y km

c) in 3rd hour

speed = 2x-y km/h

time= 1 hour

distance = 2x-y km

total distance = (x)+ (x+2y) +( 2x-y)

= x+x+2x+2y-y 》 4x+y

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