Question

2.3 into 10 to the power 22 atoms of an element weight 6.9 gram atomic weight of that element is

Answer 1

Answe--Atomic weight of the element =180.66u

Explanation:

Number of atoms present in the element= 2.3×10^22

Weight of the element =6.9g

Avogadro number=6.022×10^23

Atomic weight not the element=?

We know that number of moles=Given number of atoms÷Avodagro number

=2.3×10^22÷6.022×10^23

Number of moles= 2.3×10^22÷ 6.022 × 10^23

Number of moles= Given weight÷Atomic weight

Therefore atomic weight =Given weight× Avogadro number÷number of atoms

=6.9 ×6.022 × 10^23÷2.3 ×10^22

= 180.66 u

There fore Atomic weight of the element= 180.66u