Math, asked by keshavdev7449, 9 hours ago

2/3 log⁡27+2 log⁡2-log⁡3-1/2 log⁡16

Answers

Answered by Yashbarman472
0

Answer:

log3

Step-by-step explanation:

2/3(log3^3)+2log2-log3-1/2log2^4

by use of (xlogx=logx^x)

log(3^3)^2/3+log2^2-log3-log(2^4)^1/2

log3^2+log2^2-log3-log(2^2)

use property (logx^x=xlogx)

2log3+2log2-log3-2log2

2log3-log3+2log2-2log2

log3

hope you understand this solution

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