Question

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Answer 1

Step-by-step explanation:

† Question :-

Explain Freundlich adsorption isotherm briefly with mathematical calculations.

\large \dag† Answer :-

\rm \purple \maltese \: \: \: \red{ \underline{ \underline{Freundlich \: Adsorption \: Isotherm }}}✠

FreundlichAdsorptionIsotherm

According to Freundlich adsorption isotherm the extent of adsorption is directly proportional to fractional power of pressure.

In mathematical form :-

\bf \red\bigstar \: \: \orange{ \pmb{ \underbrace{ \underline{ \blue{ \frac{x}{m} \propto p {}^{ \ 1/n} \: \: \: }}}}}★

m

x

∝p

1/n

m

x

∝p

1/n

\begin{gathered}:\longmapsto \rm \frac{ x }{m} = kp {}^{1/n} \: ; \small0 < n < 1\: \: - - - (1) \\ \end{gathered}

:⟼

m

x

=kp

1/n

;0<n<1−−−(1)

❒ Taking log on both sides of (1) :

\begin{gathered}:\longmapsto \rm log \frac{x}{m} = log( kp {}^{1/n} )\\ \end{gathered}

:⟼log

m

x

=log(kp

1/n

)

\begin{gathered}:\longmapsto \rm log \frac{x}{m} = log(k) + log( p {}^{1/n} ) \\ \end{gathered}

:⟼log

m

x

=log(k)+log(p

1/n

)

\begin{gathered}:\longmapsto \rm log \frac{x}{m} = log(k) + \frac{1}{n} log( p ) - - - (2) \\ \end{gathered}

:⟼log

m

x

=log(k)+

n

1

log(p)−−−(2)

Also graph of both equations are given in attachment.

Answer 2

$\large\sf\pink{AnsWer:}$

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