2.3 moles of carbon gas take up 50 Liters of space, what would be the volume if the amount of moles was increased to 2.9?
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Given:
Initial no of moles of carbon gas, N1 = 2.3
Initial Volume, V1 = 50 litre
Final no of moles of carbon gas, N2 = 2.9
To Find:
Final Volume, i.e., V2
Calculation:
- According to Avogadro's law, we have:
V1/n1 = V2/n2
⇒ 50/2.3 = V2/2.9
⇒ V2 = (50 / 2.3) × 2.9
⇒ V2 = 63.043 litre
- So the volume of 2.9 moles of carbon gas will be 63.043 litre.
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