Math, asked by darshanparakh, 1 year ago

(2.3^n+1 + 7.3^n-1) ÷ (3^n+2 - 2(1/3)^1-n​

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Answered by knjroopa
106

Answer:

1

Step-by-step explanation:

2 x 3 ^n + 1 + 7 x 3^n – 1 / 3^n + 2 – 2(1/3)^1- n

We can write this as  

2 x 3^n x 3^1 + 7 x 3^n x 3^-1 / 3^n + 2 – 2 x (3^-1)^1-n

Taking 3^n as common factor we get

3^n(2 x 3 + 7 x 3^-1) /3^n+2 – 2 x 3^n-1

3^n(2 x 3 + 7 x 3^-1)/ 3^n x 3^2 – 2 x 3^n x 3^-1

3^n(2 x 3 + 7 x 3^-1)/3^n(3^2 – 2 x 3^-1)

6 + 7/3 / 9 – 2/3

25/3 / 25/3

= 1

Answered by smee26
84

Answer:

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this is your answer

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