(2.3^n+1 + 7.3^n-1) ÷ (3^n+2 - 2(1/3)^1-n
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Answered by
106
Answer:
1
Step-by-step explanation:
2 x 3 ^n + 1 + 7 x 3^n – 1 / 3^n + 2 – 2(1/3)^1- n
We can write this as
2 x 3^n x 3^1 + 7 x 3^n x 3^-1 / 3^n + 2 – 2 x (3^-1)^1-n
Taking 3^n as common factor we get
3^n(2 x 3 + 7 x 3^-1) /3^n+2 – 2 x 3^n-1
3^n(2 x 3 + 7 x 3^-1)/ 3^n x 3^2 – 2 x 3^n x 3^-1
3^n(2 x 3 + 7 x 3^-1)/3^n(3^2 – 2 x 3^-1)
6 + 7/3 / 9 – 2/3
25/3 / 25/3
= 1
Answered by
84
Answer:
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