Question

√2-√3
prove that irrational
​

Answer 1

Answer:

it is irrational

Step-by-step explanation:

root 2 - root3 is equal to nothing

Answer 2

Let √2-√3 is rational no.

√2-√3 = p/q ( where p and q are co prime and q ≠0)

Squaring both side

(√2-√3) ²= (p/q) ²

2 - 2√6 +3 =p²/q²

√6 = -p²/2q² + 5/2

Now

LHS there is Irrational no.

And in RHS there is rational no.

This is not possible

This contradiction arise due to our wrong assumption.

Thus, our assumption is wrong

√2-√3 is Irrational no.

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Hope it helps!!

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