2/3 rd of 9 subtracted from a number is equal to 1/4 th of the sum of those number and 45. Find the number.
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Let the no. be x
2/3rd of 9 is 3
therefore, x-3 = 1/4*(x+45)
x-3 = 1/4x + 1/4*45
x-3 = x/4 + 45/4
x = 3 + x/4 + 45/4
x - x/4 = 3 + 45/4
x/1 - x/4 = 3 + 45/4
4x/4 - x/4 = 3 + 45/4
3x/4 = 3 + 45/4
3/4 * x = 3 + 45/4
x = 3 + 45/4 ÷ 3/4
x = 3 + 45/4 * 4/3
x = 3 + 15
x = 18
Therefore, 18 is the no.
2/3rd of 9 is 3
therefore, x-3 = 1/4*(x+45)
x-3 = 1/4x + 1/4*45
x-3 = x/4 + 45/4
x = 3 + x/4 + 45/4
x - x/4 = 3 + 45/4
x/1 - x/4 = 3 + 45/4
4x/4 - x/4 = 3 + 45/4
3x/4 = 3 + 45/4
3/4 * x = 3 + 45/4
x = 3 + 45/4 ÷ 3/4
x = 3 + 45/4 * 4/3
x = 3 + 15
x = 18
Therefore, 18 is the no.
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