Question

2 3) The first harmonic frequency of a transverse stationary wave on a stretched string of length L = 0.5 m and mass per unit length 0.01 kg/m is 247 Hz. What is the tension on the string?​

Answer 1

Answer:

idk

Explanation:

Answer 2

Given:

First harmonic frequency (f) = 247 Hz

Length(L) = 0.5 m

Mass per unit length ($\mu$) = 0.01 kg/m

To find:

The tension on the string.

Step by step explanation:

We know that,

$f = \frac{1}{2L} \sqrt{\frac{T}{\mu} }$

$f *2L= \sqrt{\frac{T}{\mu} }$

$(f *2L)^{2} = {\frac{T}{\mu} }$

$(f *2L)^{2} * {\mu} }= {T}$

$T =(f *2L)^{2} * {\mu} }$

$T =(247 *2*0.5)^{2} * {0.01} }$

$T =(247)^{2} * {0.01} }$

$T = 61009* {0.01}$

$T = 610.09N$

Therefore, the tension on the string is 610.09 N.