Question

2+√3 upon 2-√3 the question is the rationlise the denominator​

Answer 1

$\frac{(2+\sqrt{3})}{(2-\sqrt{3})} \\= \frac{(2+\sqrt{3})(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3})}\\= \frac{(2+\sqrt{3})^{2}}{2^{2}-(\sqrt{3})^{2}}\\= \frac{2^{2} + (\sqrt{3})^{2} + 2 \times 2 \times \sqrt{3}}{ 4 - 3} \\= 4 + 3 + 4\sqrt{3} \\= 7 + 4\sqrt{3}$

Therefore.,

$\red{\frac{(2+\sqrt{3})}{(2-\sqrt{3})}}\\\green {= 7 + 4\sqrt{3}}$

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