Math, asked by 29riyav, 1 year ago

23^x+1-63^x-1-3^x=9

Answers

Answered by spp84

3

=(2x3^x-6x3^x)-3^x=9

=2x3^x(1-3)-3^x=9

=(2x3^x)(-2)-3^x=9

=-4x3^x-3^x=9

=-3^x(4+1)=9

=-3^x=9/5

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