Math, asked by priyanshukoge18, 2 months ago

(-2/3)^x × (-2/3)^6 = (-2/3)^16

Answers

Answered by utsavraj83

0

Answer:

Here base are samr so take exponent and solve

Step-by-step explanation:

(-2/3)^x+6=(-2/3)^16 (a^m*a^n=a^m+n)

x+6=16

x=16-6

x=10

hope it helps!!

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