Math, asked by morningmist, 2 months ago

2 × 3^x+2 + 3^x+1 = 63
find the value of x

Answers

Answered by pru52

3

Answer:

2 × 3^x × 3^2 + 3^x × 3^1 = 63

3^x(2×3^2 +3) = 63

3^x (18+3) = 63

3^x = 63/21

3^x = 3^1

x = 1

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