(2.3)x=(.23)y=1000then find the value of 1/x-1/y
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(2.3)x = (.023)y = 1000
x = 1000/2.3 = 10000/23
y = 1000/0.23 = 100000/23
1/x - 1/y = 1/(10000/23) - 1/(100000/23)
= 23/10000 -23/100000
=(230-23)/100000
=207/100000
=2.07 × 10^-3
x = 1000/2.3 = 10000/23
y = 1000/0.23 = 100000/23
1/x - 1/y = 1/(10000/23) - 1/(100000/23)
= 23/10000 -23/100000
=(230-23)/100000
=207/100000
=2.07 × 10^-3
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