Question

(2*3)^x (3*2)^2x = 81*16,then x=

Answer 1

(2*3)^x * (3*2)^2x = 81*16

6^x *6^2x = 3^4 *2^4 since 81 = 3*3*3*3 = 3^4 and 16 = 2*2*2*2 = 2^4

6^x+2x = (3*2)^4 here a^m*a^n = a^m+n
6^3x= 6^4
therefore
3x = 4
x= 4/3