Math, asked by randhir54, 11 months ago

2^30+2^29-2^28/2^31+2^30+2^29​

Answers

Answered by ihrishi
4

Answer:

 \frac{ {2}^{30}  +  {2}^{29} -  {2}^{28}  }{ {2}^{31} +  {2}^{30}   +  {2}^{29} }  =  \frac{ {2}^{28}( {2}^{2}  + 2 - 1) }{ {2}^{29}(  {2}^{2}  + 2 + 1} ) \\  =  \frac{4 + 1}{2(4 + 2 + 1)}  =  \frac{5}{2  \times 7}  \\  =  \frac{5}{14}

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