2^30+2^29+2^28 divide by 2^31+2^30-2^29
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Answered by
5
See in these types of questions you have to take some terms common.
Taking 2^28 common from both numerator and denominator; We get 2^28(2^2 +2^1 + 1)/ 2^28(2^3+2^2-2^1)
=2^28(4+2+1)/2^28(8+4-2)
=2^28(7)/2^28(10)
2^28 in the numerator and denominator will cancel out and we will be left with 7/10. So the ANSWER IS 7/10.
Taking 2^28 common from both numerator and denominator; We get 2^28(2^2 +2^1 + 1)/ 2^28(2^3+2^2-2^1)
=2^28(4+2+1)/2^28(8+4-2)
=2^28(7)/2^28(10)
2^28 in the numerator and denominator will cancel out and we will be left with 7/10. So the ANSWER IS 7/10.
raman7:
thanks for your quick response
Your welcome :)
Answered by
2
Taking2^28 common
2^28(2^2+2^1+2^0)/2^28(2^3+2^2-2^1)
Cancelling 2^28
We get (4+2+1)/(8+4-2)
7/10 is the ans
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