Question

2 310
An electric circuit works on 220
Vand 5 A current values. When
the current passes for 5 second
what is the value of Heat
developed in the circuit- *
O 5500 J
O 5000J
O 1200 J
O None of the above
​

Answer 1

$\huge\sf\pink{Answer}$

☞ Your Answer is Option A

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$\huge\sf\blue{Given}$

✭ Potential difference = 220 V

✭ Current = 5 A

✭ Time = 5 sec

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$\huge\sf\gray{To \:Find}$

◈ The heat produced?

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$\huge\sf\purple{Steps}$

So here we shall first find the resistance of the circuit,for that we shall use the Ohm's Law, that is,

$\underline{\boxed{\sf V=IR}}$

Substituting the given values,

➳ $\sf V=IR$

➳ $\sf 220 = 5 \times R$

➳ $\sf \dfrac{220}{5} = R$

➳ $\sf \red{R= 44 \ \Omega}$

So now that we know the Resistance the heart produced is given by,

$\underline{\boxed{\sf H = I^2Rt}}$

Substituting the values,

➝ $\sf H = I^2Rt$

➝ $\sf H= 5^2 \times 44 \times 5$

➝ $\sf H=25\times 44 \times 5$

➝ $\sf \orange{H = 5500 \ J}$

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Answer 2

Solution :

$\underline{\bf{Given\::}}}$

• Potential difference, (V) = 220 Volt
• Current, (I) = 5 Ampere
• Time, (t) = 5 sec.

$\underline{\bf{Explanation\::}}}$

$\underbrace{\bf{1^{st} \:Case\::}}}$

Using formula of the ohm's law according to the given question;

$\boxed{\bf{V=IR}}$

$\mapsto\sf{V=IR}\\\\\mapsto\sf{220 = 5 \times R}\\\\\mapsto\sf{R=\cancel{220/5}}\\\\\mapsto\bf{R=44\: \Omega}$

$\underbrace{\bf{2^{nd} \:Case\::}}}$

Using formula of the joule's law of heating or joule equation's of heating;

$\boxed{\bf{H=I^{2} Rt}}}$

• Resistance,(R) = 44$\Omega$

• Current, (I) = 5 A
• Time, (t) = 5 seconds .

On putting the values, we have;

$\mapsto\sf{H=I^{2} Rt}\\\\\mapsto\sf{H= (5)^{2} \times 44\times 5}\\\\\mapsto\sf{H=25 \times 44 \times 5}\\\\\mapsto\bf{H=5500\:J}$

Thus;

The value of heat develop in the circuit is 5500 Joule .

Option (a)