У =2х + 32\5x+ 4a ; make x as subject
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Step-by-step explanation:
y = (2x + 32)/(5x + 4a)
on cross-multiplication
y(5x + 4a) = (2x + 32)
=> 5xy + 4ay = 2x + 32
=> 5xy - 2x = 32 - 4ay
=> x( 5y - 2) = 32 - 4ay
=> x = (32 - 4ay) / (5y - 2)
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