Question

2. 320 J of heat is produced in 10 s in a 2 omh's
resistor. Find the
amount of current flowing through the resistor.

Answer 1

$\huge{ \dag{ \underline{ \bold{ \red{Question...}}}}}$

✳320 J of heat is produced in 10 s in a 2 omh's

resistor. Find the amount of current flowing through the resistor....?

$\huge{ \dag{ \underline{ \bold{ \red{Answer..}}}}}$

$\large{ \sf{current \: flowing \: = 4 \: amperes}}$

$\huge{ \dag{ \underline{ \bold{ \red{Solution...}}}}}$

$\large{ \bold{ \star{ \underline{given...}}}}$

• Heat produced = 320 joules
• Time taken = 10 sec
• Resistance = 2 ohms

$\large{ \star{ \bold{ \underline{to \: find...}}}}$

• Current flow...

$\large{ \sf{ \to \: u \: must \: know...}} \\ \\ \large{ \red{ \sf{joule \: 1st \: law \: of \: heating...}}} \\ \huge{ \boxed{ \sf{ \boxed{ \green{Q= I {}^{2} Rt}}}}} \\ \\ \large{ \sf{ where \: Q= \: heat \: produced}} \\ \\ \large{ \sf{ I = current \: flow}} \\ \\ \large{ \sf{ R = resistance \: of \: body}} \\ \\ \large{ \sf{t = time \: taken}}$

$\large{ \sf{ \red{by \: using \: formula...}}} \\ \\ \large{ \sf{ \implies{320 = I {}^{2} \times 2 \times 10}}} \\ \\ \large{ \sf{ \implies{320 = 20 \times I {}^{2} }}} \\ \\ \large{ \sf{ \implies{I {}^{2} = \cancel{ \frac{320}{20} }}}} \\ \\ \large{ \sf{ \implies{ I {}^{2} = 16}}} \\ \\ \large{ \sf{ \implies{ \purple{ \boxed{ I = 4 \: amperes}}}}}$

$\large{ \diamond{ \bold{ \underline{ \orange{current \: flowing = 4 \: amperes }}}}}$

☯️More About this law...

• The amount of generated heat is proportional to wire’s electrical resistance when the current in the circuit and the flow of current is not changed.

• The amount of generated heat in a conductor carrying current is proportional to the square of the current flow through the circuit when the electrical resistance and current supply is constant.

• The amount of heat produced because of the current flow is proportional to the time of flow when the resistance and current flow is kept constant.