2.38g of uranium was heated strongly in a current of air the resulting weight of the compound was 2.806g . Determine the empirical formula of the oxide.
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Mass of oxygen that combined with uranium = 2.806 - 2.38
= 0.426
Moles of oxygen = 0.426/16 = 0.026625
Moles of uranium = 2.38/238 = 0.01
Mole ratio: Oxygen = 0.026625/0.01 = 2.66 ≈ 2
Uranium = 0.01/0.01 = 1
The formula of Uranium oxide is UO2
= 0.426
Moles of oxygen = 0.426/16 = 0.026625
Moles of uranium = 2.38/238 = 0.01
Mole ratio: Oxygen = 0.026625/0.01 = 2.66 ≈ 2
Uranium = 0.01/0.01 = 1
The formula of Uranium oxide is UO2
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