Question

(2/3a^2b^2c^2+4/3ab^2c^2) divided by 1/2abc. divide the polynomial by the given monomial​

Answer 1

Answer is linked.

Hope you like it.

Answer 2

$\frac{4}{3} bc (a+2)$

Step-by-step explanation:

The given polynomial is

$\frac{2}{3}a^2b^2c^2+ \frac{4}{3}ab^2c^2$

given monomial is $\frac{1}{2}abc$

we have to divide the  polynomial by the given monomial​

then

dividing seperately the terms of the polynomial

$(\frac{\frac{2}{3} a^2b^2c^2 }{\frac{1}{2}abc } ) + (\frac{\frac{4}{3} ab^2c^2 }{\frac{1}{2}abc } )$

we get

$\frac{4}{3 } abc + \frac{8}{3}bc$

taking common $\frac{4}{3} bc$

= $\frac{4}{3} bc (a+2)$

hence , on dividing we get $\frac{4}{3} bc (a+2)$

#Learn more:

Divide the given polynomial by monomial 15(a^3b^2c^2-a^2b^3c^2+a^2b^2c^3÷3abc

https://brainly.in/question/2206772