Math, asked by piyush7696dada, 23 days ago

2/3a²b+3/2ab²-1/6ab-a²b+4/3a²b-4/6ab​

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Answered by ajitgodakhindi
1

Answer:

Given   : 2/3a^2b+3/2ab^2-1/6ab-a^b+4/3a^2b-4/6ab

Rearranging like terms

=2/3a^2b-a^2b+4/3a^2b+3/2ab^2-1/6ab-4/6ab

= a^2b(2/3-1+4/3)+3/2ab^2-ab(1/6+4/6)

= a^2b+3/2ab^2-5/6 ab

= ab(a+3/2b-5/6)

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