(2/3ab+3/2c square) (4/3ab-3/2c square) simplify
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Step-by-step explanation:
The given polynomial is
\frac{2}{3}a^2b^2c^2+ \frac{4}{3}ab^2c^2
3
2
a
2
b
2
c
2
+
3
4
ab
2
c
2
given monomial is \frac{1}{2}abc
2
1
abc
we have to divide the polynomial by the given monomial
then
dividing seperately the terms of the polynomial
(\frac{\frac{2}{3} a^2b^2c^2 }{\frac{1}{2}abc } ) + (\frac{\frac{4}{3} ab^2c^2 }{\frac{1}{2}abc } )(
2
1
abc
3
2
a
2
b
2
c
2
)+(
2
1
abc
3
4
ab
2
c
2
)
we get
\frac{4}{3 } abc + \frac{8}{3}bc
3
4
abc+
3
8
bc
taking common \frac{4}{3} bc
3
4
bc
= \frac{4}{3} bc (a+2)
3
4
bc(a+2)
hence , on dividing we get \frac{4}{3} bc (a+2)
3
4
bc(a+2)
#Learn more:
Divide the given polynomial by monomial 15(a^3b^2c^2-a^2b^3c^2+a^2b^2c^3÷3abc
https://brainly.in/question/2206772
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