2.3g of na reqcts with water . calculate the mass of naoh formed. what will be the volume of h2 evolved at ntp
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Answer:
The given reaction is, 2Na+2H2O→2NaOH+H2
From equation, it is evident :
46gNa reacts to liberate 1 mole H2
∴23gNa reacts to liberate (1×23)/46=1/2moleH2
∴ Weight of H2 liberated =(1/2)×2=1g
Also, volume of H2
at STP =22400×
2
1
=11200mL
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