Question

2+3i/1+2i make it inti a+ib form

Answer 1

Answer:

$\frac{2 + 3 i}{1 + 2i} \times \frac{1 - 2i}{1 - 2i} \\ \frac{(2 + 3i)(1 - 2i)}{1 - (4 \sqrt{ (- 1\: ) {}^{2} } } = \frac{2 - 4i + 3i + 6}{5} \\ = \frac{8 - i}{5}$

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