Question

2-√3i/1 + i in a+ib form​

Answer 1

Answer:

(2- √3i)/(1+ i)

= (2-√3i)(1 - i)/ (1² - i²)

= (2 - √3 -2i - √3i)/ (1+1)

= (2-√3)/2  + i(-2 - √3)/2

∴ a = (2 - √3)/2

 b = (-2 -√3)/2

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Step-by-step explanation:

Answer 2

$\frac{2 - \sqrt{3} i}{1 + i} \\ \\ = \frac{2 - \sqrt{3}i }{1 + i} \times \frac{1 - i}{1 - i} \\ \\ = \frac{2 - 2i - \sqrt{3} i + \sqrt{3} {i}^{2} }{1 - {i}^{2} } \\ \\ = \frac{2 - 2i - \sqrt{3}i - \sqrt{3} }{2} \\ \\ = \frac{(2 - \sqrt{3} ) - i(2 + \sqrt{3} )}{2} \\ \\ = \frac{2 - \sqrt{3} }{2} + i[- ( \frac{2 + \sqrt{3} }{2} )]$