Question

(-2+3i)+3(-1/2i+1)-(2i) express in the form a+ib ​

Answer 1

Answer:

Multiplying both numerator and denominator by the Complex conjugate of the denominator

Multiplying both numerator and denominator by the Complex conjugate of the denominatorTherefore,

Multiplying both numerator and denominator by the Complex conjugate of the denominatorTherefore,(3+4i)(2−3i)=3+4i2−3i×3−4i3−4i

Multiplying both numerator and denominator by the Complex conjugate of the denominatorTherefore,(3+4i)(2−3i)=3+4i2−3i×3−4i3−4i=(3)2−(4i)2(2−3i)(3−4i)

Multiplying both numerator and denominator by the Complex conjugate of the denominatorTherefore,(3+4i)(2−3i)=3+4i2−3i×3−4i3−4i=(3)2−(4i)2(2−3i)(3−4i)=9+16(6+12i2)−(9+8)i

Multiplying both numerator and denominator by the Complex conjugate of the denominatorTherefore,(3+4i)(2−3i)=3+4i2−3i×3−4i3−4i=(3)2−(4i)2(2−3i)(3−4i)=9+16(6+12i2)−(9+8)i=25−6−17i

Multiplying both numerator and denominator by the Complex conjugate of the denominatorTherefore,(3+4i)(2−3i)=3+4i2−3i×3−4i3−4i=(3)2−(4i)2(2−3i)(3−4i)=9+16(6+12i2)−(9+8)i=25−6−17i=25−6+25−17i

Multiplying both numerator and denominator by the Complex conjugate of the denominatorTherefore,(3+4i)(2−3i)=3+4i2−3i×3−4i3−4i=(3)2−(4i)2(2−3i)(3−4i)=9+16(6+12i2)−(9+8)i=25−6−17i=25−6+25−17iHere, A=25−6 and B=25−17